We say that a number is coruñese if, in its decimal representation, there are no two consecutive digits that are the same.
Given $$$n$$$, express $$$n$$$ as the sum of two non-negative coruñese integers.
The first line contains an integer $$$T$$$, the number of cases to process.
This is followed by $$$T$$$ lines, each containing an integer $$$n$$$.
For each case, write a line with two coruñese numbers $$$a$$$ and $$$b$$$, such that $$$a + b = n$$$. The numbers $$$a$$$ and $$$b$$$ must be written in decimal without leading zeros. You can print any valid solution.
5 1 11 2 2025 1337
0 1 6 5 1 1 2020 5 1216 121
$$$1 \leq T \leq 10^4$$$.
$$$1 \leq n \lt 10^{10^5}$$$, and the sum of the number of digits of $$$n$$$ for all cases will be at most $$$10^5$$$.