A. Candies
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Recently Vova found $$$n$$$ candy wrappers. He remembers that he bought $$$x$$$ candies during the first day, $$$2x$$$ candies during the second day, $$$4x$$$ candies during the third day, $$$\dots$$$, $$$2^{k-1} x$$$ candies during the $$$k$$$-th day. But there is an issue: Vova remembers neither $$$x$$$ nor $$$k$$$ but he is sure that $$$x$$$ and $$$k$$$ are positive integers and $$$k > 1$$$.

Vova will be satisfied if you tell him any positive integer $$$x$$$ so there is an integer $$$k>1$$$ that $$$x + 2x + 4x + \dots + 2^{k-1} x = n$$$. It is guaranteed that at least one solution exists. Note that $$$k > 1$$$.

You have to answer $$$t$$$ independent test cases.

Input

The first line of the input contains one integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. Then $$$t$$$ test cases follow.

The only line of the test case contains one integer $$$n$$$ ($$$3 \le n \le 10^9$$$) — the number of candy wrappers Vova found. It is guaranteed that there is some positive integer $$$x$$$ and integer $$$k>1$$$ that $$$x + 2x + 4x + \dots + 2^{k-1} x = n$$$.

Output

Print one integer — any positive integer value of $$$x$$$ so there is an integer $$$k>1$$$ that $$$x + 2x + 4x + \dots + 2^{k-1} x = n$$$.

Example
Input
7
3
6
7
21
28
999999999
999999984
Output
1
2
1
7
4
333333333
333333328
Note

In the first test case of the example, one of the possible answers is $$$x=1, k=2$$$. Then $$$1 \cdot 1 + 2 \cdot 1$$$ equals $$$n=3$$$.

In the second test case of the example, one of the possible answers is $$$x=2, k=2$$$. Then $$$1 \cdot 2 + 2 \cdot 2$$$ equals $$$n=6$$$.

In the third test case of the example, one of the possible answers is $$$x=1, k=3$$$. Then $$$1 \cdot 1 + 2 \cdot 1 + 4 \cdot 1$$$ equals $$$n=7$$$.

In the fourth test case of the example, one of the possible answers is $$$x=7, k=2$$$. Then $$$1 \cdot 7 + 2 \cdot 7$$$ equals $$$n=21$$$.

In the fifth test case of the example, one of the possible answers is $$$x=4, k=3$$$. Then $$$1 \cdot 4 + 2 \cdot 4 + 4 \cdot 4$$$ equals $$$n=28$$$.