You are given an integer $$$n$$$ and $$$m$$$ intervals. Each interval is of the form $$$[l_i, r_i]$$$ and satisfies $$$1 \le l_i \le r_i \le n$$$. Note that there can be duplicate intervals.
Let $$$p$$$ be a permutation of length $$$n$$$ containing all the integers $$$0,1,2,\dots,n-1$$$ exactly once.
There is a multiset $$$M$$$ which is initially empty.
For each interval $$$[l_i, r_i]$$$:
After processing all the intervals, $$$M$$$ will be equal to $$$\{v_1, v_2, \dots, v_m\}$$$.
Your task is to construct a permutation $$$p$$$ of length $$$n$$$ containing all the integers $$$0,1,2,\dots,n-1$$$ exactly once such that $$$\operatorname{mex}(M)$$$ is minimized.
$$$^{\text{∗}}$$$$$$\operatorname{mex}(a)$$$ denotes the minimum excluded (MEX) of the integers in $$$a$$$. For example, $$$\operatorname{mex}([2,2,1])=0$$$ because $$$0$$$ does not belong to the array, and $$$\operatorname{mex}([0,3,1,2])=4$$$ because $$$0$$$, $$$1$$$, $$$2$$$, and $$$3$$$ appear in the array, but $$$4$$$ does not.
The first line contains a single integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases. Description of each testcase follows.
The first line contains two integers $$$n$$$ and $$$m$$$ ($$$3 \le n \le 3000$$$, $$$1 \le m \le 3000$$$).
The next $$$m$$$ lines each contain two space-separated integers $$$l_i, r_i$$$ ($$$1 \le l_i \le r_i \le n$$$) each denoting an interval.
It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$3000$$$, and the sum of $$$m$$$ over all test cases does not exceed $$$3000$$$.
For each testcase, print a permutation $$$p$$$ of length $$$n$$$ containing all the integers $$$0,1,2,\dots,n-1$$$ exactly once such that $$$\operatorname{mex}(M)$$$ is minimized.
If there are multiple answers, you may print any one of them.
53 11 23 51 11 22 22 22 34 51 22 33 41 14 45 43 51 12 44 44 21 32 4
2 0 12 1 00 2 1 32 0 1 3 43 1 0 2
For the first testcase, if we choose to construct $$$p = [2, 0, 1]$$$, then $$$M = \{\operatorname{mex}(2, 0)\} = \{1\}$$$. Now, $$$\operatorname{mex}(M) = 0$$$.
For the third testcase, if we choose to construct $$$p = [0, 2, 1, 3]$$$, then $$$M = \{\operatorname{mex}(0, 2), \operatorname{mex}(2, 1), \operatorname{mex}(1, 3), \operatorname{mex}(0), \operatorname{mex}(3)\} = \{1, 0, 0, 1, 0\}$$$. Now, $$$\operatorname{mex}(M) = 2$$$.
For the fourth testcase, if we choose to construct $$$p = [2, 0, 1, 3, 4]$$$, then $$$M = \{\operatorname{mex}(1, 3, 4), \operatorname{mex}(2), \operatorname{mex}(0, 1, 3), \operatorname{mex}(4)\} = \{0, 0, 2, 0\}$$$. Now, $$$\operatorname{mex}(M) = 1$$$.
For the fifth testcase, if we choose to construct $$$p = [3, 1, 0, 2]$$$, then $$$M = \{\operatorname{mex}(3, 1, 0), \operatorname{mex}(1, 0, 2)\} = \{2, 3\}$$$. Now, $$$\operatorname{mex}(M) = 0$$$.