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Results

1.
By Nickolas, 14 years ago, translation, In English
Codeforces Round #105 (Div. 2): editorial So, here goes the editorial. I'll tell you right away that nobody guessed [user:MikeMirzayanov,2012-02-02]'s problem (nice disguise, er?) --- it was problem C about the picky princess. Actually, this was the first problem of the round, the rest of problems I invented to keep up the lovely topic. [problem:148A] The number of dragons D can be quite small, so the problem can be solved in a straightforward way, by iterating over dragons 1 through D and checking each dragon individually. Time complexity of such solution is O(D). [cut] There exists a smarter solution with O(1) complexity, based on inclusion-exclusion principle. You'll have to count the numbers of dragons which satisfy at least one, two, three or four of the damage conditions $N_i$, i.e., dragons who have index divisible by LCM of the corresponding sets of numbers. Remember that the number of numbers between 1 and D which are divisible by T equals $D / T$. Finally, the number of dragons that get damaged equals $N_...
straightforward way, by iterating over dragons 1 through D and checking each dragon individually. Time

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2.
By Agnimandur, 3 years ago, In English
Recursive Dragon is HIRING Hello. If you're talented at competitive programming and interested in working for Recursive Dragon as a mentor, send me a message on Codeforces or through Discord (Agnimandur#9256). ![ ](https://i.imgur.com/FBVFGJ5.png)
Recursive Dragon is HIRING, Hello. If you're talented at competitive programming and interested in working forRecursive Dragon

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