Approach↵
==================↵
We will solve two parts separately. First lets find the min number of moves.<br>↵
Let `n` be the size of s and `m` be the size of t.↵
Minimum number of moves.↵
------------------↵
Let `ans[l][r]` denote minimum number of moves to delete all occurrence of t in `s[l]...s[r]`.<br>↵
1. if there is no index `j`, in `[l,r]` such that `j+m-1 < r` and `s[j...j+m-1] == t` then `ans[l][r] = 0`.<br>↵
2. else for all `j`'s described above `ans[l][r] = min(ans[l][r], ans[l][j-1] + 1 + ans[j+m][r])` <br>↵
The minimum number of moves are `ans[0][n-1]`.<br>↵
<br>↵
<br>↵
Number of ways to achieve those minimum number of ways.↵
------------------↵
### Observations↵
1.
==================↵
We will solve two parts separately. First lets find the min number of moves.<br>↵
Let `n` be the size of s and `m` be the size of t.↵
Minimum number of moves.↵
------------------↵
Let `ans[l][r]` denote minimum number of moves to delete all occurrence of t in `s[l]...s[r]`.<br>↵
1. if there is no index `j`, in `[l,r]` such that `j+m-1 < r` and `s[j...j+m-1] == t` then `ans[l][r] = 0`.<br>↵
2. else for all `j`'s described above `ans[l][r] = min(ans[l][r], ans[l][j-1] + 1 + ans[j+m][r])` <br>↵
The minimum number of moves are `ans[0][n-1]`.<br>↵
<br>↵
<br>↵
Number of ways to achieve those minimum number of ways.↵
------------------↵
### Observations↵
1.
