Can we solve problem 1920C - Partitioning the Array faster in O(n*d(n)) ~ O(n^(4/3))?
I'm getting interested in it.
→ Pay attention
→ Streams
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | tourist | 3985 |
| 2 | jiangly | 3814 |
| 3 | jqdai0815 | 3682 |
| 4 | Benq | 3529 |
| 5 | orzdevinwang | 3526 |
| 6 | ksun48 | 3517 |
| 7 | Radewoosh | 3410 |
| 8 | hos.lyric | 3399 |
| 9 | ecnerwala | 3392 |
| 9 | Um_nik | 3392 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 169 |
| 2 | maomao90 | 162 |
| 2 | Um_nik | 162 |
| 4 | atcoder_official | 161 |
| 5 | djm03178 | 158 |
| 6 | -is-this-fft- | 157 |
| 7 | adamant | 155 |
| 8 | awoo | 154 |
| 8 | Dominater069 | 154 |
| 10 | luogu_official | 150 |
→ Find user
→ Recent actions
History
Revisions
| Rev. | Lang. | By | When | Δ | Comment | |
|---|---|---|---|---|---|---|
| en3 |
|
a_little_cute | 2024-01-14 07:53:04 | 4 | Tiny change: 'C] faster in O(n*d(n)' -> 'C] faster than O(n*d(n)' | |
| en2 |
|
a_little_cute | 2024-01-14 07:52:29 | 2 | Tiny change: 'O(n*d(n)) ~ O(n^(4/3)' -> 'O(n*d(n)) ≈ O(n^(4/3)' | |
| en1 |
|
a_little_cute | 2024-01-14 07:52:11 | 136 | Initial revision (published) |
Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Dec/22/2024 21:17:35 (j3).
Desktop version, switch to mobile version.
Supported by
