So, I participated in Codeforces Round 1089 (Div. 2) recently and solved ABC1, and when I moved on to C2 I thought to myself "wow, that's a big difficulty jump!"

After the contest was over, I also thought about whether there is a way to put a number to this, and after a bit of thinking, I came up with the following process:

• Take the solve counts of each problem (the green numbers at the bottom of the Standings page). Call it $$$\mathrm{solves}$$$.
• The imbalance is the standard deviation of the logarithms of the consecutive ratio