why I can't find subarray correctly?

Revision en1, by DNNJFM, 2016-07-31 19:14:05

To clarify, "subarray" is defined like, for example: if A="abc" B="??a???b????c???" then A is subarray of B.

Tags subarray

History

 
 
 
 
Revisions
 
 
  Rev. Lang. By When Δ Comment
en5 English DNNJFM 2016-07-31 19:30:36 2 Tiny change: '&& B[curB]==c ) curB+' -> '&& B[curB]!=c ) curB+' (published)
en4 English DNNJFM 2016-07-31 19:25:51 14 Tiny change: 'of B, but I get AC, II get WA:' -> 'of B, but versionI get AC, versionII get WA:' (saved to drafts)
en3 English DNNJFM 2016-07-31 19:24:47 537 Tiny change: ' string.\n~~~~~\nc' - (published)
en2 English DNNJFM 2016-07-31 19:15:22 201
en1 English DNNJFM 2016-07-31 19:14:05 149 Initial revision (saved to drafts)