While I do understand that the merge operation can be deduced from the equation (a + b)^2 = a^2 + b^2 — 2ab I could not specifically figure out how would I formulate the merge operation. Any help is really appreciated.
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Segment Tree Problem from SPOJ, SEGSQRSS — Sum of Squares with Segment Tree
While I do understand that the merge operation can be deduced from the equation (a + b)^2 = a^2 + b^2 — 2ab I could not specifically figure out how would I formulate the merge operation. Any help is really appreciated.
Rev. | Язык | Кто | Когда | Δ | Комментарий | |
---|---|---|---|---|---|---|
en2 | Tobby_And_Friends | 2016-10-21 22:52:23 | 58 | Tiny change: 'While I do' -> 'Problem Link: http://www.spoj.com/problems/SEGSQRSS/\n\nWhile I do' | ||
en1 | Tobby_And_Friends | 2016-10-21 22:05:32 | 299 | Initial revision (published) |
Название |
---|