suppose u have to find a % b , i see many red coders solution instead of using directly a%b they do like ..
if (a >=mod) a-=mod ??
why so ?
why +/i instead on %
suppose u have to find a % b , i see many red coders solution instead of using directly a%b they do like ..
if (a >=mod) a-=mod ??
why so ?
| Rev. | Lang. | By | When | Δ | Comment | |
|---|---|---|---|---|---|---|
| en1 |
|
vintage_Petr_Mitrichev | 2019-01-01 13:51:36 | 166 | Initial revision (published) |
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | turmax | 3559 |
| 6 | tourist | 3541 |
| 7 | strapple | 3515 |
| 8 | ksun48 | 3461 |
| 9 | dXqwq | 3436 |
| 10 | Otomachi_Una | 3413 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 157 |
| 2 | adamant | 153 |
| 3 | Um_nik | 147 |
| 4 | Proof_by_QED | 146 |
| 5 | Dominater069 | 145 |
| 6 | errorgorn | 141 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | TheScrasse | 134 |
| 10 | chromate00 | 133 |
