| # | User | Rating |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3823 |
| 3 | Benq | 3738 |
| 4 | Radewoosh | 3633 |
| 5 | jqdai0815 | 3620 |
| 6 | orzdevinwang | 3529 |
| 7 | ecnerwala | 3446 |
| 8 | Um_nik | 3396 |
| 9 | ksun48 | 3390 |
| 10 | gamegame | 3386 |
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 167 |
| 2 | Um_nik | 163 |
| 3 | maomao90 | 162 |
| 3 | atcoder_official | 162 |
| 5 | adamant | 159 |
| 6 | -is-this-fft- | 158 |
| 7 | awoo | 157 |
| 8 | TheScrasse | 154 |
| 9 | Dominater069 | 153 |
| 9 | nor | 153 |
How can I solve this range quarry problem?
Let array a1,...,an, ( 1<= n <= 10^6 )
3 kinds of quarries, m in total ( 1<= m <= 10^6 )
1 l r k: add k to al, ..., ar
2 l r k: change ai ( l<= i <=r ) in to max( ai , k )
3 l r: print max( al, ... ,ar )
I think it could be done it at mlogn by segment tree. How can I?
