let there be 3 integers x, y, z

their multiplication (x * y * z) is can be calculated either as (x * y) * z or x * (y * z) // associativity holds

now assume x / (y * z) = x * (1 / y) * (1 / z)

let Y and Z be the multiplicative modular inverse of (1 / y) and (1 / z) respectively

then result can be written as x * Y * Z

here (x * Y) * Z != x * (Y * Z) { WHY ? } // associativity does not holds