How to solve this problem.
I saw it in a contest conducted on 13 March 8:00PM-11:00PM IST .
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I didn't implement this solution and don't know if this will work or not.
Construct a segment tree where the nodes have a frequency array. Using this type of segment tree we can find the frequencies of all letters in the range [l,r] in $$$O(logN)$$$ time.
Now once we know the frequencies ,we can quickly judge if that sub segment can be re arranged as a palindrome.
If a palindrome is possible, find the compressed version of the palindrome. ( For example the compressed version of this string aaabbccccd will be a:3 b:2 c:4 d:1 ). After you know the compressed version you will have to lazily propagate the changes i.e. new frequencies . Since the length of the compressed string can be at max 53 (palindrome like abcde...yzazy.....dcba) and lazy propagation works in logN , this approach will hopefully pass.
Thanks.
Implemented the same and passed 90% of the testcases rest TLED. But this can be done 100% with this approach.
You will be shocked to know that I used brute force and 90% passed
I think that the testcases were very weak for 5th and 6th problem .
Can u tell your approach for problem 5?
let mx[i] = maximum character in the string s[i....n] Notice that since we need to reverse only 1 substring so we should reverse the string starting at index i and ending at index j , s.t. (s[i]!=mx[i] and s[j]=mx[i] and i<j and i is as small as possible ) Now value of i can be found in O(N) and value of all j's can be found in O(N) as well.
Time complexity is O(N^2) passed because of Weak TC
So , now we can check for all j by traversing on the length x of the new string and comparing character which will be at x'th position for the new strings .New string are string formed after reversing substring from i to j .
First I thought of O(n^2) solution but didn't implemented as it would give tle
There is O(NlogN) as well which uses string Hashing and Binary search . Let there be 2 values l,m in the vector containing j , so now we can binary search the first element that differs after reversing s[i...l] and s[i...m] , hash value can be used to check whether string of length mid are equal or not .
P.S.: This one is what I thought at first , but I just went for O(N^2) solution at first
Were you able to solve the 4th problem ?
Problem Statement:
Given a tree consisting of N nodes , find minimum no. of edges to be removed to get atleast one component of size K for all(1<=K<=N).
1<=N<=1000
I was only able to solve 2 problems with all the test cases passed
How the subsequence with product's unit digit is k would be solved???¿????
It's a Dynamic programming problem , for the ith element there are two option only , either this element can be included or it can't be .
dp[i][j] denotes no. of subsequences considering first i element that have value at unit digit equal to j .
Transition are : dp[i+1][(j*(a[i]%10))%10]+=dp[i][j]; (i.e. current element is included )
dp[i+1][j]+= dp[i][j]; (i.e. current element isn't included )
Hey did you solved that problem in which chalk was to be divided into pieces by k children's in which we had to find the minimized maximum chalk length
and also for this subsequence with product's unit digit is k can you please provide the code.
Minimum maximum chalk length can be solved by binary search on answers
I found some of the test cases were giving faulty results. For ex, N = 3 and K = 0 with Arr = { 2 , 6 , 0 } should return value as 6 but the judge was considering value = 3 for such case.
Also N = 2 and K = 2 with Arr = {7 , 17} . The return value should be 8 but the judge was expecting 7.
I tried using maps but was getting caught up in test cases like this.
for n = 2 k = 2 a = {7,17} return value is 7. 7,17 7,10,7 (17 = 7+10) k = 1 7,5,5,7 (10 = 5+5) k = 2
They were not allowing to use max heap(priority queue). So I had to use vector & sort it again & again that's why it resulted in TLE. Still, 72% of the test cases passsed.
U should have just included it's header file . It might have worked .
Yes it can be done by applying dp on the flattened tree.
First flatten the tree using euler tour and then take dp[i][num_removed] which means we have covered all the subtrees with exit time less than i and total nodes removed is num_removed.
LHS means Left hand side of the equation
Like for the first example given there euler tour is something like
n=6, edges={0,1},{0,2},{2,3},{2,5},{3,4}
euler tour: 0 1 2 3 4 5
(here coincidence is in_time is same as node number(not necessary))
initially
for all
initialise
if we take the first subtree at that start at time 0
then transition
(I rooted the tree at node 0)}
if we not cut current subtree that start at time i
and ith ans is
//dp[n-i] is excluded when i=n
in[],out[] times and node_at[] can be calculated with simple DFS
70% test cases passed
The test cases which were not passing because of some validator error like this, incorrect and is shown even when right ans is outputted
What is LHS ?
Plz check the lastest edit and LHS is left hand side
Okkk .
So in this solution of yours u r considering that if we delete an edge from i->j such that j is a descendent of i , we don't need to delete any other edge in the subtree of j ?
Right if we deleted an edge , that would delete a complete subtree and we won't be able to delete any other edge in the deleted subtree
And state defining choices are we delete a subtree ofcouse by deleting an edge or not
Ok , thanks
Hey plz look at the images in spoiler and
can you tell why even correct output is marked incorrect?
and
one more thing I wanna add is when I downloaded the testcases even they were downloading not the same question
U returned a vector of size n+1 rather than of the the size n , maybe that's the reason . I have no idea about testcases , I too faced same issue.
Can someone help me with this
Did anyone get a mail regarding placements from codekaze ? Could you mention your national rank, graduation year and graduation year rank if you did receive a mail regarding placements?
They asked to fill Google form National rank 497 Graduation year rank 104
What year are you in and when did you get the mail?
I haven't received any details about placements from codekaze.
National rank: 393
Graduation rank: 252
Pre-final year
is there any way i can test my approach for this and other problem that were asked in the contest.(I cannot took part in the contest but want to upsolve)?.
Thanks in advance.
Has anyone received Amazon gift card?
I have not received it yet . I have filled the google form which they have send but not received the voucher till now what should I Do.