http://mirror.codeforces.com/contest/281/problem/D
can somebody suggest an approach to this problem
http://mirror.codeforces.com/contest/281/problem/D
can somebody suggest an approach to this problem
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | dXqwq | 3436 |
| 8 | Radewoosh | 3415 |
| 9 | Otomachi_Una | 3413 |
| 10 | Um_nik | 3376 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | adamant | 152 |
| 3 | Proof_by_QED | 146 |
| 3 | Um_nik | 146 |
| 5 | Dominater069 | 144 |
| 6 | errorgorn | 141 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 9 | TheScrasse | 134 |
| Name |
|---|



i looked at that can u please explain what is happening
for each number in the sequence A[i],
We define: MaxRight[i] = r ... where r is the smallest index where A[r]>A[i] and r>i
Also MaxLeft[i] = l ... where l is the largest index where A[l]>A[i] and l<i
If we checked the intervals [i,r] (A[r] XOR A[i]) , [l,i] (A[l] XOR A[i]) and [l,r] (A[l] XOR A[i]) for each index i ... We will cover all possible answers for any interval.
Now we need to find an efficient way to compute MaxRight[i] and MaxLeft[i]
For Computing MaxLeft[i] ... I'll check A[i-1] ...
if A[i-1] > A[i] ... Then, MaxLeft[i]=i-1
else ... we will need to check A[MaxLeft[i-1]] (Previously computed value)
Till we find the first maximum to the left.
The Same strategy can be done for MaxRight[i] ... but we will need to check A[i+1] instead and we will compute the values in reversed order.