Given an array of size n.You need to select those two different indices such that quirk between them is maximum.Quirk Q(i,j)=
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3880 |
2 | jiangly | 3669 |
3 | ecnerwala | 3654 |
4 | Benq | 3627 |
5 | orzdevinwang | 3612 |
6 | Geothermal | 3569 |
6 | cnnfls_csy | 3569 |
8 | jqdai0815 | 3532 |
9 | Radewoosh | 3522 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | awoo | 161 |
2 | maomao90 | 160 |
3 | adamant | 156 |
4 | maroonrk | 153 |
5 | atcoder_official | 148 |
5 | -is-this-fft- | 148 |
5 | SecondThread | 148 |
8 | Petr | 147 |
9 | nor | 144 |
10 | TheScrasse | 142 |
Given an array of size n.You need to select those two different indices such that quirk between them is maximum.Quirk Q(i,j)=
Название |
---|
Auto comment: topic has been updated by ram396 (previous revision, new revision, compare).
Can elements of A be negative?
No
Well if elements aren't negative then j should always be equal to n. And i you can traverse in linear time to find the maximum.
Edit: only if c is +ve, otherwise j can be other things.
If $$$A[i]$$$ or $$$c$$$ is allowed to be negative:
Note that:
We define the following functions:
For each $$$j$$$, you need to find $$$i$$$ such that $$$F(j) + M(i)j + C(i)$$$ is maximized. You can use convex hull trick to do so in $$$O(N \lg N)$$$ time.
That is a wonderful new thing which probably won't be useful for me to learn at this stage, but can you take a quick look at the latest question I asked in my blogs here? I think this problem can be solved using what you call a "convex hull trick" ? Am I right?. In brief I want the maximum of $$$a_1(K - i) - b_1, a_2(K - i) - b_2, \ldots, a_n(K - i) - b_n$$$ after each time I change i from 0 to K — 1.
can u provide the code?