Hello, I tried to solve this problem with Suffix Array : 452E - Three strings . I have seen some solution but unable to understand the idea. Can anyone give me the idea to solve the problem using Suffix Array?
Hello, I tried to solve this problem with Suffix Array : 452E - Three strings . I have seen some solution but unable to understand the idea. Can anyone give me the idea to solve the problem using Suffix Array?
| № | Пользователь | Рейтинг |
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| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | turmax | 3559 |
| 6 | tourist | 3541 |
| 7 | strapple | 3515 |
| 8 | ksun48 | 3461 |
| 9 | dXqwq | 3436 |
| 10 | Otomachi_Una | 3413 |
| Страны | Города | Организации | Всё → |
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| 1 | Qingyu | 157 |
| 2 | adamant | 153 |
| 3 | Um_nik | 147 |
| 4 | Proof_by_QED | 146 |
| 5 | Dominater069 | 145 |
| 6 | errorgorn | 141 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | TheScrasse | 134 |
| 10 | chromate00 | 133 |
| Название |
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This is my rough idea:
abc$bc%cbc) and compute its SA and LCP:C. For each of the three stringsSand each (necessary) lengthL, maintain the number of suffixTofSthat is already seen such thatC[1...L]==T[1...L].This is my actual code: 7273217. The numbers I maintained is put in
stack<T> st;. I (unnecessarily) used binary index tree for range-modification.