Here is the link to the editorial. Feel free to discuss problems and ask me questions. I'll be glad to improve the editorial with your comments.
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3880 |
2 | jiangly | 3669 |
3 | ecnerwala | 3654 |
4 | Benq | 3627 |
5 | orzdevinwang | 3612 |
6 | Geothermal | 3569 |
6 | cnnfls_csy | 3569 |
8 | jqdai0815 | 3532 |
9 | Radewoosh | 3522 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | awoo | 161 |
2 | maomao90 | 160 |
3 | adamant | 156 |
4 | maroonrk | 153 |
5 | atcoder_official | 148 |
5 | -is-this-fft- | 148 |
5 | SecondThread | 148 |
8 | Petr | 147 |
9 | nor | 144 |
10 | TheScrasse | 142 |
Название |
---|
I'm not getting div2 c ...how it is linked to knapsack?? can you explain the logic more clearly??
We want to find the probability of gaining i scores in games other than G. It's similar to finding in how many ways we gain i scores. It's a knapsack problem.
we need to gain i scores in such a way that after adding G to it .It must become greater than n*(n+1)/4.In other words we need to look for only those i's such that after adding G to it ,it can become greater than n*(n+1)/4.Am i right?
and we'll use knapsack to find those i's and we won't be using G as a weight?
Correct.
Thank you :)