How to solve this kattis problem? It is a multi-source but not once, one by one. You should count the number of vertices with the distance at least k after each source is added. Restarting dijkstra every time is not enough.
Thanks.
→ Pay attention
→ Streams
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | tourist | 3985 |
| 2 | jiangly | 3814 |
| 3 | jqdai0815 | 3682 |
| 4 | Benq | 3529 |
| 5 | orzdevinwang | 3526 |
| 6 | ksun48 | 3517 |
| 7 | Radewoosh | 3410 |
| 8 | hos.lyric | 3399 |
| 9 | ecnerwala | 3392 |
| 9 | Um_nik | 3392 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 169 |
| 2 | maomao90 | 162 |
| 2 | Um_nik | 162 |
| 4 | atcoder_official | 161 |
| 5 | djm03178 | 158 |
| 6 | -is-this-fft- | 157 |
| 7 | adamant | 155 |
| 8 | awoo | 154 |
| 8 | Dominater069 | 154 |
| 10 | luogu_official | 150 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Dec/22/2024 17:53:25 (l2).
Desktop version, switch to mobile version.
Supported by
Take advantage of K being small. Maybe incorporate into state somehow?
Define nodes based on two parameters (location, distance from alien base). Run a modified Dijkstra where you find the minimum input id of an alien base that can reach each node. This works because if two alien bases can both reach a town with the same distance D, then for all other nodes reachable from this node, the base with smaller id will always get there earlier.
Srry, I don't understand your solution. Can you describe little bit more about it? Or provide code if you have written it. Thanks.
https://ideone.com/ER1jNn
Thanks, I got it. By the way, isn't there more standard (closer to standard dijkstra) solution?