| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | turmax | 3559 |
| 6 | tourist | 3541 |
| 7 | strapple | 3515 |
| 8 | ksun48 | 3461 |
| 9 | dXqwq | 3436 |
| 10 | Otomachi_Una | 3413 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 157 |
| 2 | adamant | 153 |
| 3 | Um_nik | 147 |
| 4 | Proof_by_QED | 146 |
| 5 | Dominater069 | 145 |
| 6 | errorgorn | 141 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | TheScrasse | 134 |
| 10 | chromate00 | 133 |
| Name |
|---|



It's pretty much Knapsack DP.
I will mention the dynamics:
$$$dp_{i,j,0}\ =maximum \ amount \ paid\ for\ first\ i\ elements\ with\ sweetness\ \lt =j\ and\ operation\ is not\ used.$$$
$$$dp_{i,j,1}\ =maximum \ amount \ paid\ for\ first\ i\ elements\ with\ sweetness\ \lt =j\ and\ operation\ is\ used.$$$
$$$Transitions\ are\ similar\ to\ Knapsack\ DP.$$$
Your answer will be $$$max(dp[n][m][0]\ ,\ dp[n][m][1])$$$
My solution: https://ideone.com/NgqsT4
Brother please can you clear my doubt I use 3 dp states dp[n][m][flag] The code passed the test cases but when I was using 2 dp states dp[n][m] and was updating the value for flag . Then it was failing on few cases why is so???
This is my previous code:- https://pastebin.com/E1hqm56H
This is new code:- https://pastebin.com/xEqn2Uq8
The problem is with the statement
, since we don't know if flag was true or false, in the returned state,so it may lead to overcount.
Thanks I understood my mistake