Stepavly's blog

Codeforces Round #719 (Div. 3)
By Stepavly, 4 years ago, translation, In English

Unfortunately, due to Internet provider network issues, we have to postpone the round. The current plan, that the round is postponed by 24 hours, will start on May/05/2021 17:35 (Moscow time).

Hello, Codeforces!

<almost-copy-pasted-part>

Hello! Codeforces Round #719 (Div. 3) will start at May/05/2021 17:35 (Moscow time). You will be offered 7 problems with expected difficulties to compose an interesting competition for participants with ratings up to 1600. However, all of you who wish to take part and have a rating 1600 or higher, can register for the round unofficially. The round will be hosted by rules of educational rounds (extended ICPC). Thus, during the round, solutions will be judged on preliminary tests, and after the round, it will be a 12-hour phase of open hacks. I tried to make strong tests — just like you will be upset if many solutions fail after the contest is over.

You will be given 7 problems and 2 hours to solve them.

Note that the penalty for the wrong submission in this round (and the following Div. 3 rounds) is 10 minutes.

Remember that only the trusted participants of the third division will be included in the official standings table. As it is written by link, this is a compulsory measure for combating unsporting behavior. To qualify as trusted participants of the third division, you must:

  • take part in at least two rated rounds (and solve at least one problem in each of them),
  • do not have a point of 1900 or higher in the rating.

Regardless of whether you are a trusted participant of the third division or not, if your rating is less than 1600, then the round will be rated for you.

The problems for this round were invented by MikeMirzayanov, Supermagzzz, Stepavly and Aris.

Thanks to Gassa, BledDest, Programmer, bugdone, ruban, RedAnt, songsinger and Gornak40 for help with testing the round.

Thanks to MikeMirzayanov for platforms and coordination of our work. Good luck!

</almost-copy-pasted-part>

Editorial is ready!

  • Vote: I like it
  • +275
  • Vote: I do not like it

Comments Comments (326)
| Write comment?
»
4 years ago, # |
  Vote: I like it -71 Vote: I do not like it

Most awaited round of the month.

→ Reply
»
4 years ago, # |
  Vote: I like it +26 Vote: I do not like it

My first rated contest pretty excited :)

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +21 Vote: I do not like it

    First rated contest with a new Alt? :P

    → Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +42 Vote: I do not like it

    My first unrated div 3 :)

    → Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 3   Vote: I like it +2 Vote: I do not like it

    Everyone !! Did any Rating changes occurred I am unable to see any rating changes for me, So here I am asking ! -_-

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
      ← Rev. 3   Vote: I like it 0 Vote: I do not like it

      Same here, and even it is showing in unrated contest in my profile

      however I am on official standings

      Can't wait for rating changes.

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
          Vote: I like it 0 Vote: I do not like it

        Until rating is actually credited/debited in your profile, Every contest is shown in unrated.

        → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      They just did another system testing. Wait for 2 hours now and hope no more system testings.

      → Reply
»
4 years ago, # |
  Vote: I like it +55 Vote: I do not like it

→ Reply
»
4 years ago, # |
  Vote: I like it -15 Vote: I do not like it

Sorry but I don't really understand the trusted rules :( Does that mean I can't use clones?

→ Reply
»
4 years ago, # |
  Vote: I like it -46 Vote: I do not like it

Div. 4 when?

→ Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 3   Vote: I like it -41 Vote: I do not like it

    What is div 4 ?

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
      ← Rev. 2   Vote: I like it +15 Vote: I do not like it

      Does a contest always mean solving hard problems :)? Even a div. 4 contest with easy/tricky problems can be fun at times.
      What I think is, coding is not always about solving hard problems, let there be fun.

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
          Vote: I like it +2 Vote: I do not like it

        I can't disagree, but what's the point of solving easy problems if they don't bring you any benefit, just a waste of time? is not it ?

        → Reply
        • »
          »
          »
          »
          »
          4 years ago, # ^ |
            Vote: I like it +2 Vote: I do not like it

          I think solving easier problems(which we can solve faster), can be a really good warm-up.
          Sometime when I feel dull, or like I am unable to perform well, I go for solving some easier problems. That really helps in gaining pace.

          → Reply
          • »
            »
            »
            »
            »
            »
            4 years ago, # ^ |
              Vote: I like it +3 Vote: I do not like it

            yes, agreed but most of the people asking for div 4 are generally doing it just in hope of positive rating.

            → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      nice argument

      → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +11 Vote: I do not like it

      Funny calling him noob when he has a rating higher than you.

      → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +12 Vote: I do not like it

Really excited for my second contest , hoping i would cross 1000 this time. Any tips are welcomed. TIA

→ Reply
»
4 years ago, # |
  Vote: I like it -18 Vote: I do not like it

how to become red coder in 1 month???? any tips and tricks???

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +40 Vote: I do not like it

    Yes, just win every contest you step in and you'll be red within a month

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +39 Vote: I do not like it

    Wait for January 2022, you will don't have to wait a month, 1 sec would be good enough. xD

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +6 Vote: I do not like it

    I became a LGM in January and posted on social media just to baffle my friends.

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    start in December and when new year comes, they will give you an option to change your color for few days. That's my secret of becoming a red coder.

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    yes, there are two ways either you paint your laptop screen with red colour , or solve 3000 plus questions in a month ,lol

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    Few years ago，when the initial Rating was 1500,LxL became gold only after three div.2s.

    Becoming red in 1 month? Just go to bed and have a good dream. There is everything in dreams.

    → Reply
»
4 years ago, # |
  Vote: I like it +13 Vote: I do not like it

Hmmm, why aren't we seeing vovuh as a problem setter in recent div.3 contests?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +2 Vote: I do not like it

    Stepavly contests are like the old DIV 3.5, Vovuh DIV 3's were, indeed, a bit tricky especially the latter problems.

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Hope to see a cool problemset. Best of luck, All.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +16 Vote: I do not like it

    As a tester I can assure you the problem set is cool :)

    Also be sure to read all the problems. Setters often write this, but in Div2 I think most of the time the last problems are really hard. But for Div3 I think it's really worth doing it (at least reading the first N-1 problems in a N problem set).

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +2 Vote: I do not like it

      why doesn't this comment has the number of upvotes it deserves.

      → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +9 Vote: I do not like it

      Hmm note that testers are usually part of conspiracies. So the N'th problem could be the easiest, we should try to solve that first.

      → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it 0 Vote: I do not like it

One more new author of div 3 *o*
Hope I become pupil again

→ Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +22 Vote: I do not like it

I still remember the time when vovuh was a coordinator of Div3, it has been so long.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it -31 Vote: I do not like it

    *has, try improving your grammar. Would really go a long way in interview preparation.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
      ← Rev. 3   Vote: I like it +15 Vote: I do not like it

      try not correcting others' grammar errors. would really go a long way in your interview process if interviewer's grammar isnt that great:)

      → Reply
»
4 years ago, # |
  Vote: I like it -60 Vote: I do not like it

please schedule the contest 1 hr earlier as it perfectly ends before dinner and good discussion time before going to sleep

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +21 Vote: I do not like it

    You don't know how many time zones in the world, do you?

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +5 Vote: I do not like it

    This request is the perfect definition for self centered.

    → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +3 Vote: I do not like it

...

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it -11 Vote: I do not like it

    Again, that's impossible. If you have good delta you have bad delta. If you have extremely good delta, you have extremely bad delta.

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

I can leave a message again Yea~

→ Reply
»
4 years ago, # |
  Vote: I like it -15 Vote: I do not like it

can i say that div 3 is the best training contest for who is less than 1600 rating and will be better if problem standard

→ Reply
»
4 years ago, # |
  Vote: I like it -32 Vote: I do not like it

→ Reply
»
4 years ago, # |
  Vote: I like it +21 Vote: I do not like it

It seems that the queue is really long......Can this round hold on time?

→ Reply
»
4 years ago, # |
  Vote: I like it +4 Vote: I do not like it

Verdict: In queue

→ Reply
»
4 years ago, # |
  Vote: I like it +8 Vote: I do not like it

There is a problem with submission, it shows the "In Queue" verdict. Wish this will not happen in today's contest.

→ Reply
»
4 years ago, # |
  Vote: I like it +12 Vote: I do not like it

Anyone else getting Bad Gateway errors lately?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +4 Vote: I do not like it

    Yes, I think there is a server issue on cf.

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    Hope this won't occur during contest , DIV3s are imp for beginners.

    → Reply
»
4 years ago, # |
  Vote: I like it +8 Vote: I do not like it

Notice unusual change in schedule.. :(

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +5 Vote: I do not like it

    I think it's better to have a postponed rated round than an unrated round
    (it doesn't matter to you as it is already unrated for you :D)

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Delayforces!!! :(

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

It's been an hour since I submitted a problem. Still in queue :(

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

um so how many registrations will this round have now?

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

The least they can do is to reset the participants so that there won't be another 30k contest and it becomes unrated, seems like no one cares about div.3 contests.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    What do you mean by no one cares about div.3 contests?

    → Reply
»
4 years ago, # |
  Vote: I like it +36 Vote: I do not like it

It's my first time to see a 24-hour delay here.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Nooo :((

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Peeporiot ;-;

→ Reply
»
4 years ago, # |
  Vote: I like it +15 Vote: I do not like it

Better delay than unrated :(

→ Reply
»
4 years ago, # |
  Vote: I like it +6 Vote: I do not like it

So,30k+ participants this time?

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

round is postponed, I was waiting and refreshing every 1 minute to see how much time left. sad life.

→ Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

Since the contest was postponed, can you please open the registration again?

→ Reply
»
4 years ago, # |
  Vote: I like it +9 Vote: I do not like it

Div 3 — Let's rock today.

(postponed :{ )-

Let's practice today :}

→ Reply
»
4 years ago, # |
  Vote: I like it +11 Vote: I do not like it

due to Internet × wait until the registered participants over 30k √

→ Reply
»
4 years ago, # |
  Vote: I like it -60 Vote: I do not like it

I finished my talk over phone with bae just 5 mins before the contest only to know this... (Cry Emoji)

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

All this time.. i was refreshing my browser..thinking issue on my side.

→ Reply
»
4 years ago, # |
  Vote: I like it -20 Vote: I do not like it

The round has been postponed- NO WORRIES

IPL has been postponed- CRY, CRY, CRY :(

→ Reply
»
4 years ago, # |
  Vote: I like it -60 Vote: I do not like it

postponed for 24 hours! I will never participate in a CF contest if this contest has been postponed again!

→ Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +3 Vote: I do not like it

Stepavly please enable the register button so that the people who have not registered and are the official trusted participants can register !! ** Thanks in advance ** !!

UPD : THANKS !! I have successfully registered now !

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

when I finish my dinner fast for the contest...

Unfortunately, due to Internet provider network issues, we have to postpone the round

→ Reply
»
4 years ago, # |
  Vote: I like it +6 Vote: I do not like it

→ Reply
»
4 years ago, # |
  Vote: I like it +101 Vote: I do not like it

.
Pics-Art-05-04-08-18-05

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +2 Vote: I do not like it

    you are genius bro!

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +2 Vote: I do not like it

    and then 24 more hours for ratings change. I don't know whats there in calculating ratings that takes 2 or more hours.

    → Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Verdict: No Color! :(

→ Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +8 Vote: I do not like it

Cf: Hmm you're mad because we delay the round for 5 min sometimes WEll How About 24 hours !! Muahaha

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

Really excited for the contest , hoping I would cross 1100 this time. Any tips are welcomed. TIA

→ Reply
»
4 years ago, # |
  Vote: I like it +4 Vote: I do not like it

→ Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Good luck to everyone!

→ Reply
»
4 years ago, # |
  Vote: I like it +7 Vote: I do not like it

gM0ZCR.png when you heard the round was delayed

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

This will be my second contest. I participated in last global round and I still don't know how the score works perfectly. In that contest I think they gave me less points for a problem with previous wrong submissions. Here when it says there's a 10 minutes penalty for wrong submission, is it saying that I will lose 10 minutes from the total 2 hours of the contest for every wrong answer?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +4 Vote: I do not like it

    You are judged by number of solved problems, and penalty points. Foreach AC submission you get 1 solved problem, and the number of minutes from start of contest plus 10 minutes per wrong submission of that problem as penalty.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      Thank you. I thought it meant I would have less time to solve problems, misunderstood that

      → Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

i have a feeling that site may crash !!!!!

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Why on equal rank in div3 contest gives less positive delta then div2 on same rank. Suppose x rank in div3 will give less positive delta than x rank in div2 ?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    coz having the same rank in a more difficult contest(since better rated participants are rated in Div2 contests, than in Div3) is better.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +1 Vote: I do not like it

      So , greater number of participation theory fails here!

      → Reply
»
4 years ago, # |
  Vote: I like it +7 Vote: I do not like it

Hope the contests won't get unrated because of long queue, we are reaching close to 30k , at this rate we might be reaching around 32k easily

→ Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it 0 Vote: I do not like it

Got It.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +2 Vote: I do not like it

    no score distribution in div3

    → Reply
»
4 years ago, # |
← Rev. 3   Vote: I like it 0 Vote: I do not like it

It's starting finally: the most awaited contest since yesterday :)

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Cheers Codeforces for 30K registrations once again!!!

→ Reply
»
4 years ago, # |
  Vote: I like it +6 Vote: I do not like it

my code is running from more than 10 min, i also tried to cout<<"HELLO"; but it also taking more than 10 min ; MY internet connectivity is good. i also tried to logout and log in

→ Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Is there any queue issue :( , my code is in the queue for last 20 minutes

→ Reply
»
4 years ago, # |
  Vote: I like it +4 Vote: I do not like it

It seems that my submission for G is executed twice, is this right...?

→ Reply
»
4 years ago, # |
  Vote: I like it +8 Vote: I do not like it

you guys should give atleast some weight to out-of-contest submissions. It's not like everyone participates in div3 :|

→ Reply
»
4 years ago, # |
← Rev. 5   Vote: I like it 0 Vote: I do not like it

;

→ Reply
»
4 years ago, # |
  Vote: I like it -38 Vote: I do not like it

THE QUEUE IS TOOOOOOO LONG I CANT STAND IT PLEASE MAKE IT UNRATED

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

After waiting for 4-5 minutes.

WA on test 1

→ Reply
»
4 years ago, # |
  Vote: I like it -15 Vote: I do not like it

Queueforces :(

→ Reply
»
4 years ago, # |
  Vote: I like it -19 Vote: I do not like it

No way this can be rated!

→ Reply
»
4 years ago, # |
  Vote: I like it +60 Vote: I do not like it

Interactive is not good when long queue time is there.

→ Reply
»
4 years ago, # |
  Vote: I like it +30 Vote: I do not like it

This Contest should have been extended by 15-20 min to compensate for long queue

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it -23 Vote: I do not like it

    what if some people have work after it ? Extending round is always a bad idea. They can keep it for 15-20 min extra but it should be announced before the contest. for majority of people queue time didn't matter much and it was fair for everyone since everything was same for everyone.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +10 Vote: I do not like it

      Actually, there have been situations in which the contest was extended due to long queue. I think it wasn't a really smart choice to put >100 cases in G considering that both F1 and F2 were interactive, though.

      → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      I agree that people may have other commitments after the contest but extension has been done many times during some the previous Div 3 Rounds and extension gives relief in some sense . if you have another work just go for it , there will always be some contest in a week after it so you can make a comeback in it to recover your rating loss

      → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

I am eagerly waiting to see test case 5 of problem "D".

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    For me the trick was storing the frequency of the difference as long long.

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    I got wrong on test 5, then I changed my min=1e18 and it got accepted... :)

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

C,D<A<<B<<<E,F1<<<<<F2<<<<<<<<<<<G I know the number of solves indicate otherwise (difficulty distribution linear from A to G) But just look at the number of wrong answers and solution size.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Can someone confirm if problem G was dijkstra ? I just submitted it and excited if my approach is correct.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    No. Brute force Dijkstra should TLE because the complexity is of the order $$$\mathcal{O}(E(G)) \sim 10^{12}$$$

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
      ← Rev. 3   Vote: I like it 0 Vote: I do not like it

      dijkstra is O(ElogV) and not O(EG) if you use min priority queue

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
        ← Rev. 2   Vote: I like it 0 Vote: I do not like it

        How is $$$E(G)$$$ not $$$10^{12}$$$? If you directly bruteforce from each teleporter you have $$$mn \sim 10^6$$$ edges from each node and so it behaves like Dijkstra on a complete graph which obviously exceeds time limits. I just dropped the $$$\log V(G)$$$ factor because removing that doesn't make my argument fail.

        → Reply
        • »
          »
          »
          »
          »
          4 years ago, # ^ |
            Vote: I like it +8 Vote: I do not like it

          there is actually a better way to do this, you can add a dummy node to which you connect all teleporters (from), and then you connect the dummy node to all teleporters (to). So in this Case you only have O(E) edges

          → Reply
          • »
            »
            »
            »
            »
            »
            4 years ago, # ^ |
              Vote: I like it 0 Vote: I do not like it

            Sorry, but I don't see how that's an improvement in the complexity.

            → Reply
            • »
              »
              »
              »
              »
              »
              »
              4 years ago, # ^ |
                Vote: I like it 0 Vote: I do not like it

              Like floki said, each cell has 4 edges going out of it (up, down, left, right), but also for each teleporter you add an additional edge to a dummy node (at most $$$nm$$$ more edges), and an edge from the dummy node to each teleporter (at most $$$nm$$$ more edges). So the total number of edges is at most $$$6nm$$$, which is reasonable but still hard to get to pass on this problem.

              → Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Google-forces

→ Reply
»
4 years ago, # |
  Vote: I like it +22 Vote: I do not like it

So, I waited 10 minutes to get a TLE on test 114 of G after the contest had ended already . LOL

→ Reply
»
4 years ago, # |
  Vote: I like it +8 Vote: I do not like it

Same problem as E

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +2 Vote: I do not like it

    How do you guys get so much time to find similar problem in google during the contest!

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +1 Vote: I do not like it

      Actually I didn't search I knew I had done it before

      → Reply
»
4 years ago, # |
  Vote: I like it +5 Vote: I do not like it

SlowForces

→ Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Waiting for this comment. In queue

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

WHAT A BAD ROUND!I must wait 8 minutes for the result of my submission.

→ Reply
»
4 years ago, # |
  Vote: I like it +4 Vote: I do not like it

I remember getting up for Kickstart round H last year, quite early in the morning, I think it was worth getting up. But not on that that day, its today, cuz problem E is literally this lol. Also Thanks to people like Galen, Ecnerwala, Neal, who posted solution to (problem E) that round that day. High rated people do have time machine xD.

→ Reply
»
4 years ago, # |
  Vote: I like it +65 Vote: I do not like it

F2 was an absolute bomb. It's been a while that I see such a beautiful problem.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +18 Vote: I do not like it

    Agreed, the rest of the problems felt very standard and paled in comparison to F2.

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +16 Vote: I do not like it

    Depends on your solution... Mine was using something like SQRT decomposition and was really boring. But the intended soln is indeed beautiful.

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Bad internet situation.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Problem B : https://www.geeksforgeeks.org/count-of-numbers-with-all-digits-same-in-a-given-range/

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

I forgot to delete a part of my code in F1 that I used to verify my solution, but since I was still in the queue I did not realize it, I feel very bad :(

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    same here i also face same problem in c i printed NO instead -1 :( when i realize contest is over :-(

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      yes, and the worst thing is that my solution was correct :(

      → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Can anyone explain problem F2 and G?

→ Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +16 Vote: I do not like it

    F2: You can query each prefix of the array with step of 8 (that is, 1, 9, 17, ...) and store the number of zeros in it. Now to answer the query, you must first binary-search these prefixes (takes 0 queries), and then search among the remaining 8 elements using exactly 3 queries. Now what happens when we change some 0 to 1? Some suffix of our array with prefixes has to be decreased by 1. To perform these operations quickly, you could use a segment tree. BIT and sqrt decomposition should also work.

    The total number of queries is t*3+n/8 ~ 5,5*10^4 < 6*10^4

    IDK if this solution is the same as the author's one, but this one seems really beautiful to me.

    G: Notice that you either don't use the portals at all or use them exactly once (since we can omit the intermediate steps). The variant without portals is solved using trivial BFS. About the case with portals: you first go from (1, 1) to a portal, then pay its cost, then the cost of the second portal, and then you go from portal 2 to the end. You can compute these sum of the portal's cost and the cost to go to this portal from (1, 1) and select the one which minimizes this quantity as the first one. The case with the second portal is symmetric.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +16 Vote: I do not like it

      For F2, you can break the interval into blocks of size 32 ([1,32], [33,64], ...) and query the number of 0s in each of them. This takes roughly 2*10^5/32 = 6250 queries. Then you can answer each k by finding its appropriate block and binary searching on it.

      Each answer will require 5 queries, so we use at most 5*10^4+6250=56250<6*10^4 queries.

      The advantage of using blocks instead of prefixes is that we only need to update a single block after each answer. Also, since we chose a block size of 32, we can directly iterate to find the block that will contain the answer (since 10^4*2*10^5/32 = 6.25*10^7).

      → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      My sqrt decomposition solution of F2 is giving wrong answer on test case 21 (queries limit exceeded). has anyone done using sqrt decomposition

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
          Vote: I like it +1 Vote: I do not like it

        for me, taking block size as $$$n^.5$$$ failed on TC 21, but taking block size as $$$n^.25$$$ worked.

        → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
        ← Rev. 2   Vote: I like it +1 Vote: I do not like it

        Taking block of sqrt(n) will not pass. In worst case with block size of n^0.5 length will be 450 and log of 450 is 8.8 ~ 9. so for 10^4 tests atleast 9*10^4 queries will be made.

        → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      It's helpful. Thanks !!

      → Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it 0 Vote: I do not like it

    For G using k+1 portals is never more optimal than using k portals. Hence we shall use either 0 or 1 portal. let cost[i][j] = minimum cost to move from [i,j] to n,m using only adjacent moves. Now for each portal do cost[i][j] += matrix[i][j] and find the minimum cost to travel from a portal to n,m. Let this value be equal to min_cost.Now the answer to the problem would be minimum cost to reach from a portal [i,j] to [1,1] + min_cost + matrix[i][j]. Which is equivalent to moving from [1,1] -> p1 -> p2 -> [n,m]. Dont forget the case when you use 0 portals.

    → Reply
»
4 years ago, # |
  Vote: I like it -22 Vote: I do not like it

Please make this round unrated. Couldn't solve the problems on time due to the waiting thing.

It took 10 mins to get the final verdict to one submission.

→ Reply
»
4 years ago, # |
  Vote: I like it -10 Vote: I do not like it

Regardless of whether you are a trusted participant of the third division or not, if your rating is less than 1600 or greater than 1600 or even equal, then the round will be un-rated for you.

→ Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

Someone confirm I'm not blind, this was the sample shown for problem F2: Image please load

So this seems to imply that you have to read in a 0 after each test case, which is a thing that some interactive problems make you do. But not this problem. When I tried to read in 0, I got runtime error on test 1, and removing that worked. So did the samples lie to me?

→ Reply
»
4 years ago, # |
  Vote: I like it +4 Vote: I do not like it

Task E : https://leetcode.com/problems/minimum-adjacent-swaps-for-k-consecutive-ones/description/

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

There should've been extra 10-15 minutes for such a long queue!

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Site was down for the last few minutes.

→ Reply
»
4 years ago, # |
  Vote: I like it +32 Vote: I do not like it

Did CF copy almost every problem today?
B — https://www.geeksforgeeks.org/count-of-numbers-with-all-digits-same-in-a-given-range/
D-https://www.geeksforgeeks.org/count-the-pairs-in-an-array-such-that-the-difference-between-them-and-their-indices-is-equal/
E-https://leetcode.com/problems/minimum-adjacent-swaps-for-k-consecutive-ones/

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +13 Vote: I do not like it

    Solving problems is faster and exciting then finding it on google! :)

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      Exciting- Very true
      But any regular CP-er has already practiced these common problems and knows where they can be exactly found.

      → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +3 Vote: I do not like it

    If you have already seen those problems somewhere before then gj here's a candy

    Let us (newbies) enjoy those quality problems.

    also imo, adding classical problems in a div3 is actually a good idea as they are hosted to improve your skill not the ratings

    but hey! you can switch the platform whenever you feel like ;)

    → Reply
»
4 years ago, # |
  Vote: I like it -9 Vote: I do not like it

Started the contest 15 minutes late, but still managed to get till F1 in 1 hr 30 minutes. My best performance so far, thanks for the round and hope it remains rated.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +10 Vote: I do not like it

    " Started the contest 15 minutes late "

    lol, you made 2 submissions before starting, thats so cool!!

    → Reply
»
4 years ago, # |
  Vote: I like it -7 Vote: I do not like it

Anybody else think that solutions should be regraded for problem G with an easier time constraint? Maybe it's just java idk :P

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Can someone tell me whats wrong in this code 115328097

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    answer can be greater than INT_MAX. initializing mini with some bigger value should work.

    → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it 0 Vote: I do not like it

If long queue would not have been there then I could have got F1 and F2 right in time.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Did someone got G?? I got WA on test-26

→ Reply
»
4 years ago, # |
  Vote: I like it +5 Vote: I do not like it

At least there should have been a 10/15mins extension of contest duration was needed due to the long queue problem. I just needed to change the answer from int to long long to get problem E AC. :(

→ Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

I'm so stupid!!! I used INT_MAX as infinity value in problem E :(

wrong ans on test 5
→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

too many copy-paste problem :(

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Did anyone else get WA on test case 37 for G? My submission if anyone wants to check it out.

My approach:

Do Dijkstra's algorithm, and find the shortest path to enter a portal (call it $$$P$$$). Then, run a multi-source Dijkstra's, with each source being a portal, and the starting distance to the portal as $$$P$$$.

In my code, the priority_queue stores <-distance, pii{i, j}>, and the distance is stored as negative, because Dijkstra's uses a min heap, while the default priority_queue<> uses a max heap.

The dijkstra lambda function is just so that I don't need to copy-paste the code.

The portal variable stores the shortest distance to a portal.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    Maybe the optimal answer may not contain a portal? It depends on how you wrote your code

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      That's not it, because I only update a node if it has a new shortest distance.

      That's the purpose of the if (dis[i][j] <= -d) continue; code.

      → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +4 Vote: I do not like it

Weak test cases for problem D. Disappointed :|

→ Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +6 Vote: I do not like it

Nice problems, but really bad problem statement in F, especially F2, description is hardly understandable, and description of input simply wrong.

I am shown as +100, but would rather see it if it were unrated.

Also the queue was slow.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    How to check expected rating change before official changes ??

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      download an extension

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
          Vote: I like it 0 Vote: I do not like it

        which extension?

        → Reply
        • »
          »
          »
          »
          »
          4 years ago, # ^ |
            Vote: I like it 0 Vote: I do not like it

          It is called "CF-Predictor", should be available by google search.

          → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
          Vote: I like it +1 Vote: I do not like it

        I use Carrot, and it works really well. Idk why it's named "Carrot" though lol

        → Reply
        • »
          »
          »
          »
          »
          4 years ago, # ^ |
            Vote: I like it 0 Vote: I do not like it

          Carrot is better than cf-predictor... (i used both)

          → Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 6   Vote: I like it 0 Vote: I do not like it

    Totally agree about F2

    It is rather confusing to say the least

    First there are too many letters to be easily comprehended. But that's not the only problem

    For example at some point they talk about "requests", then there are "queries". You would think it is different things,

    Then right after the description of the output format there is "In case of an incorrect query, -1 will be displayed" and you try to match with the format, thinking that maybe you need to read some confirmation code after you cout the answer because it is natural to think outputing the answer is a kind of query

    Finally there is brilliant statement "Then t lines follow, each of which contains one integer k". I don't know about others but for me it means that at this point I can read t lines.

    Yes, it is possible to figure out what was meant by rereading the samples and 1KB statement a few times or by requesting clarificiation, but I find it rather inconvenient. It is especially inconvenient when the server barely works.

    → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it 0 Vote: I do not like it

Can someone please help, why is this giving TLE in test 3 ? 115323338 , 1520F2 - Guess the K-th Zero (Hard version) Thanks ! UPD: I got it, since I used RUPQ Fenwick tree I forgot to update(r+1,-v) when I update(r,v)

→ Reply
»
4 years ago, # |
  Vote: I like it +5 Vote: I do not like it

Not only the blog was almost-copy-pasted-part. But also the problems. Idk what did the testers do really test. And did not report for such well known problems.

→ Reply
»
4 years ago, # |
  Vote: I like it +4 Vote: I do not like it

I've just started getting the knack of codeforces. And I was able to solve A, B, C, D in this contest. But I was slow to think of the approaches and hence my rank is around 6k. Hopefully, I will get better at thinking fast about the solutions. If any tips that may help, please do tell me cause that would be great.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +5 Vote: I do not like it

    Practice

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    What helps me to solve problems faster is to get better at math, especially competitive math, because the easier math problems have similar styles to the first few problems in a Div3 or Div2. Also, solving Codeforces Div3's and Atcoder abc's (Atcoder Beginner Contest) was one of the biggest factors in my speed. Now I just need to improve on actually getting the solutions...

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

how to solve F1?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    Binary search the answer. Let's say you know sum(1,cur), then if cur-sum(1,cur) (which is the number of zeroes in that range) is greater than or equal to k then you know that the kth zero should be in the range [1;cur]. Else if n-sum(1,cur)<k then the kth zero is in the range ]cur;n]. So binary search over cur. 115289534 PS: sorry for not using LATEX

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    Explanation for Problem F1

    → Reply
»
4 years ago, # |
  Vote: I like it +6 Vote: I do not like it

What is the intended solution for F2???

It seems that the author's solution is just do binary search every time and avoid query one segment twice.

But there's another very beautiful solution that divides $$$1$$$ to $$$n$$$ into blocks of $$$8$$$ and use data structures to maintain.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    What is this technique of division to 8 blocks called?

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      It's not a common technique.

      That solution is only used for F2.

      → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +8 Vote: I do not like it

      It's kind of a sqrt decomposition, but it's better to use $$$8$$$ (or $$$16$$$, or $$$32$$$) instead of $$$\sqrt{n}$$$.

      → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    I maintained blocks of 32 and each time just iterated through each block until the total zeroes greater than k. Finally a binary search on the block

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      That's the solution i mean.

      Iterate through each block is about $$$1e8$$$ so it can pass.

      → Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 5   Vote: I like it 0 Vote: I do not like it

    Suppose there is a full binary tree with 18 layers, total nodes are (2^18 — 1) > n. We use this tree to do the binary search.

    So the problem is, the start node is root, find k end nodes, is it possible to cover more than (6 * 10^4) nodes?

    The optimal method is to make the k end nodes on the leaves. So the maximum covered nodes count is min(2^17, 10^4) + min(2^16, 10^4) + min(2^15, 10^4) + ... < 6 * 10^4. So the answer is no.

    We can do the binary search with simply cache to solve this problem.

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Can someone help me figure out whats wrong with my code for F1: https://mirror.codeforces.com/contest/1520/submission/115338765

It gives a weird error for test case 2

→ Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +5 Vote: I do not like it

    How to delete this comment.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it +1 Vote: I do not like it

      '0' initially stands for string it will be hidden for us so its length would be given, read the test case as 1(length of the string) 1 1.

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
          Vote: I like it +1 Vote: I do not like it

        Ok , now i get , it was not the input that i was getting from the grader , i was thinking that is the input that i was getting from the grader initially.

        → Reply
        • »
          »
          »
          »
          »
          4 years ago, # ^ |
            Vote: I like it 0 Vote: I do not like it

          Could you explain again please? I didn't quite get it sorry

          → Reply
          • »
            »
            »
            »
            »
            »
            4 years ago, # ^ |
              Vote: I like it 0 Vote: I do not like it

            I initially thought that , the input section of test case is same as the input that we will get from the interactor. I was saying now i understand where i was wrong.

            Now as for your initial question , intially you are quering with the indices as 1 and n/2 , but what happen when n was 1 , you will get 0 as a result of n/2 (integer division) but index zero is invalid in this question because indices start from 1.

            → Reply
            • »
              »
              »
              »
              »
              »
              »
              4 years ago, # ^ |
                Vote: I like it +1 Vote: I do not like it

              Ah i see... Thanks Silly mistake cost me again

              → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +4 Vote: I do not like it

.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +12 Vote: I do not like it

    Normally people who had a bad contest, always ask for unrated, Its their habit

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    The solutions were already available online, this is a major point for making the contest unrated

    → Reply
»
4 years ago, # |
  Vote: I like it +11 Vote: I do not like it

Interactive problem in cf == Binary Search

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

HackForces (+51 successful hacks)

→ Reply
»
4 years ago, # |
← Rev. 3   Vote: I like it 0 Vote: I do not like it

Can anyone share a python solution that can pass problem G? All python solution are either failed or being hacked.

→ Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Is it only me or anyone else who found E way much tougher than number of submissions of it during contest?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    It was a classical question I think. Most of the people have already done some similar kind of questions which involves taking median as a optimal strategy.

    → Reply
    • »
      »
      »
      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      bruh taking median is not optimal strategy i brute forced on all possible groups such that groups on the left are joined to this group and groups on the right are joined similarly and took minimum of all

      → Reply
      • »
        »
        »
        »
        4 years ago, # ^ |
        ← Rev. 3   Vote: I like it 0 Vote: I do not like it

        Yes your method is also correct. But taking median of indexes of all the sheep present initially to be the median of newly formed group works here. You can check my submission[submission:115335739]

        → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    Its super easy dp. Sorry for my english

    → Reply
»
4 years ago, # |
  Vote: I like it +14 Vote: I do not like it

123 pretests for G, still got hacked :(

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

When will the ratings be updated?

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

How does hacked works here? Can anybody explain. Thanks.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    The standard tests are not always perfect and may miss some problems in the submitted solutions. Your solution for problem D has a bug, because arr[i]-i may be negative and so brr[arr[i]-i]++; results in accessing memory outside of the array bounds. Someone noticed this flaw and submitted a new testcase, which triggers this bug in your code.

    → Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

The text for 1520F2 - Guess the K-th Zero (Hard version) is very misleading:

This is a hard version of the problem. The difference from the easy version is that in the hard version 1≤t≤min(n,104) and the total number of queries is limited to 6⋅104.

and adding this to the end of the problem:

To make the game more interesting, each guessed zero turns into one and the game continues on the changed array. More formally, if the position of the k-th zero was x, then after Polycarp guesses this position, the x-th element of the array will be replaced from 0 to 1.

Thanks for the problems.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

My rating is only 386. Why it's unrated for me?? Tell me, please.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    What makes you think it is unrated for you? You are on the leaderboard, it is rated for you. Dont Worry

    → Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

I think that round should've been extended, due to long queue a lot of people lost the time waiting the submission verdict.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Can anyone explain why this code is giving TLE on test 125?

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

It's taking a long long time for system testing.

→ Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

The simplest solution for problem C according to me is just print all odd numbers from 1 to n^2 and then print all even numbers. And for n = 2 it is not possible.

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

I submitted the solution of problem B during the contest and the verdict showed me accepted. Now in my submissions list it's showing that my solution is still in queue. How it is done please someone elaborate, I'm new here. This was my second time participating in any contest.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    System testing is carrying on now. It will execute all submissions again. You just have to wait until the system testing ended.

    → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it 0 Vote: I do not like it

Hello!

I've submitted 3 solutions for F2 with C++17(64) and C++14, but it kept on giving me "in queue", did I do anything wrong? I tried to submit another problem with C++17(64) and it worked correctly.

Here are my submittions: 115402170 115401934 115401509

thank you!

UPD: It's fixed now, thank you!

→ Reply
»
4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

Is the contest unrated ?

→ Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

Why haven't the ratings been updated yet? It's not like the contest has been made unrated: there's no official announcement.

→ Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

when there will be a change in ratings ?

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

when will rating come ?

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

I have a rating < 1600 but somehow i didn't get rated for this contest.

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +3 Vote: I do not like it

    just wait for it, nobody received the rating changes yet

    → Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it +1 Vote: I do not like it

Felt unpleasant for G -_-#
I suppose it will let solutions with correct time complexity but huge constant pass ......
I need to use -Ofast to pass with time 2994ms ......

→ Reply
»
4 years ago, # |
← Rev. 2   Vote: I like it 0 Vote: I do not like it

Is the round unrated?? If so then atleast give an announcement. People are waiting since yesterday

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

its not the good thing that now above 20 hr completed after round start but ratings are not yet given

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    You can use CF-Predictor. If you not cheated and the round is rated your rating change will be approximately the same as CF-Predictor says. Don't worry your rating will be up today.

    → Reply
»
4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

for unexpected queue i coludn't find my wrong for problem F1 otherwise I could solve it

→ Reply
»
4 years ago, # |
  Vote: I like it +5 Vote: I do not like it

System testing is happening again. Isn't it already happened 2-3 hours ago?

→ Reply
  • »
    »
    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +1 Vote: I do not like it

    I think it's happening again because all the hacks weren't processed by the time previous system testing happened.

    → Reply
»
4 years ago, # |
  Vote: I like it +11 Vote: I do not like it

testforces

→ Reply
»
4 years ago, # |
  Vote: I like it -6 Vote: I do not like it

If the round had to be unrated they should have announced during the contest ,so now its confusing seeing the contest in unrated section xD

→ Reply
»
4 years ago, # |
  Vote: I like it +2 Vote: I do not like it

Dream has reached the goal [The System Testing...Again...]

→ Reply
»
4 years ago, # |
  Vote: I like it +13 Vote: I do not like it

Hopefully, they finish System Testing before tomorrow's round :(

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Why are sources evaluated that many times?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +7 Vote: I do not like it

    The first system testing forgot to add hacking testcases,so they have to test it again...

    → Reply
»
4 years ago, # |
← Rev. 3   Vote: I like it 0 Vote: I do not like it

Again system testing!!! I am eagerly waiting for the rating update.

→ Reply
»
4 years ago, # |
  Vote: I like it +5 Vote: I do not like it

Contest 1 days postponed:....:

Rating update : Hey I am following you contest

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

System tests have finished.....**FOR NOW**

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Is it rated?

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    yeah, just wait for rating

    → Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    They have performed system testing twice. Obviously, it's rated but probably there's some technical fault in testing procedure today.

    → Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Ratings aren't coming because there are still some codes in the hacks section IN QUEUE

→ Reply
  • »
    »
    4 years ago, # ^ |
      Vote: I like it +1 Vote: I do not like it

    They are in queue from last night and still its going....

    → Reply
»
4 years ago, # |
  Vote: I like it +10 Vote: I do not like it

→ Reply
»
4 years ago, # |
  Vote: I like it +8 Vote: I do not like it

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

what does this mean +40 in delta section it's showing for 2-3 minutes and then going off

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

My solution for D failed system tests, I can't seem to find the bug in my code, can anyone help? I tried the same approach as in the editorial

115278462

→ Reply
»
4 years ago, # |
  Vote: I like it +7 Vote: I do not like it

Hey MikeMirzayanov! Can you please check these 4 submissions? 115269387, 115321811 115286392, 115315037 I think it's obvious that these two contestants are cheating and the system did nothing about it!

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

How is the rating calculated?

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Can someone tell me why I got a 'failed system test(tle)' using trivial BFS for problem G? And the same code got an AC just by using a different compiler. GNU C++11 998 ms AC: https://mirror.codeforces.com/contest/1520/submission/115447927 GNU C++17 (64) 3000ms FST: https://mirror.codeforces.com/contest/1520/submission/115322035

→ Reply
»
4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Just fell upon a question very similar to q4 of this contest-- https://mirror.codeforces.com/contest/1398/problem/C

→ Reply