tishrah's blog

Logic for question "The Artful Expedient" 869A ?????
By tishrah, history, 5 years ago, In English

Simply printing System.out.println("Karen"); passes all the test case of this question.

Is there any logic behind it or it was simply my luck and a mere coincidence ?????

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5 years ago, hide # |
 
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Your streak is awesome but you should try practicing problems of higher difficulty, because the percentage of problems you have solved with rating >= 1200 is just 10 percent of your total solved problems and that's really low. I hope you would find this advice helpful.

Have a look at the level of the problems you have solved here.

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    5 years ago, hide # ^ |
     
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    one gray guy teaching another gray guy OK

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      5 years ago, hide # ^ |
       
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      You can correct me if I said something wrong. The advice of solving problems higher than your current rating is not my advice it's what I have learnt from red coders like errichto etc. Also I said something which is quite obvious and is correct even if a gray says it, idk where you get that logic that if gray says something about cp that makes it invalid or less worthy to consider.

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        5 years ago, hide # ^ |
         
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        it's less worth just because u don't have enough experience. I have a question: if ur advice is good why are u still gray? now the author says that's ok giving advice but to me it looks like someone ask a question about task and another man with no reason starts to giving advice)

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5 years ago, hide # |
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I think it because if $$$a$$$ $$$xor$$$ $$$b$$$ == $$$c$$$ it means that $$$a$$$ $$$xor$$$ $$$c$$$ = $$$b$$$, so if you found indexes $$$i$$$ and $$$j$$$ and $$$a_i$$$ $$$xor$$$ $$$b_j$$$ $$$=$$$ (number in second array), you can choose this number and get $$$a_i$$$ $$$xor$$$ (this number) = $$$b_j$$$. If this number in first array, you can choose (this number) $$$xor$$$ $$$b_j$$$ = $$$a_i$$$. So if you found pair you can also find another pair.

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