| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3823 |
| 3 | Benq | 3738 |
| 4 | Radewoosh | 3633 |
| 5 | jqdai0815 | 3620 |
| 6 | orzdevinwang | 3529 |
| 7 | ecnerwala | 3446 |
| 8 | Um_nik | 3396 |
| 9 | ksun48 | 3390 |
| 10 | gamegame | 3386 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | cry | 167 |
| 2 | Um_nik | 163 |
| 3 | maomao90 | 162 |
| 3 | atcoder_official | 162 |
| 5 | adamant | 159 |
| 6 | -is-this-fft- | 158 |
| 7 | awoo | 157 |
| 8 | TheScrasse | 154 |
| 9 | Dominater069 | 153 |
| 9 | nor | 153 |
TLE code : https://mirror.codeforces.com/contest/1613/submission/137709567
Accepted code : https://mirror.codeforces.com/contest/1613/submission/137711275
The only difference is:
AC : fin(i,0,n){ cout<<v[i]<<"\n"; }
TLE : fin(i,0,n){ cout<<v[i]<<endl; }
I know endl is supposed to be a bit slower because it flushes the output, but how is the difference significant enough to give a TLE?
The difference is significant in problems where you have to output multiple lines. The small differences add up.
\endlis much slower than\nbecause of the flushing of the output buffer. In general, just use\nto be safe.