Im unable to understand the solution logic of codeforces div2 664 problem c. http://mirror.codeforces.com/contest/1395/problem/C
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Im unable to understand the solution logic of codeforces div2 664 problem c. http://mirror.codeforces.com/contest/1395/problem/C
I tried to solve longest increasing subsequence in top down but only pass few cases i don't know whether it is full right or wrong here is the code which i tried
this question is from leetcode
int lis(vector<int>&nums,int i,int n,int prev,vector<int>& ls){ if(i==n||n==0){ return 0; } if(ls[i]!=-1){ return 1 ; } lis(nums,i+1,n,prev,ls); if(nums[i]>prev){ int num=1+lis(nums,i+1,n,nums[i],ls); ls[num]=1; return num; } return 0; } class Solution { public: int lengthOfLIS(vector<int>& nums) { int n=nums.size(); int c; vector<int> ls(n+1,-1); lis(nums,0,n,INT_MIN,ls); for(int i=n;i>=0;i--){ if(ls[i]!=-1){ c=i; break; } else{ c=0; } } if(nums.size()==0){ return 0; } else{ if(c==0){ return 0; } else{ return c; } } } };
I wants to how to write top-down approach of this question and wants to know the solution of this question in c++ can anyone explain me ?
Here is the link https://mirror.codeforces.com/contest/1000/problem/C I saw the editorial but cannot understand please explain the solution of this question.
The question is
https://mirror.codeforces.com/contest/489/problem/C
#include<bits/stdc++.h> #include<math.h> using namespace std; int main(){long long int j,no,i,sum1,sum,d=0,d2=0,rem=0,i1,large,large1=0; cin>>j>>no; if(j>6){ cout<<0<<" "<<0; } if(j<6){ if(no==0){ cout<<-1<<" "<<-1; } else{ for(i=(pow(10,j)-1);i>=pow(10,(j-1));i--){ sum1=0; sum=0; i1=i; while(i1!=0){ rem=i1%10; sum1=sum1+rem; sum=(sum*10)+rem; i1=i1/10; } if(sum1==no){ d2=i; large=i; if(large1<=large){ large1=large; } } } if(no>1){ cout<<d2<<" "<<large1; } if(no==1){ cout<<i+1<<" "<<i+1; } } } return 0; }
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