• Recently I came across a new idea to solve graph-related problems using segment trees, I would like to discuss the same with a problem.

Problem:

Given a graph $$$G$$$ with $$$N$$$ nodes and many edges (around $$$O(N^2)$$$), the goal is to perform Dijkstra algorithm on this dense graph and find out the shortest path from node 1 to all other nodes.

The edges are given in a compressed format. The input follows $$$M$$$ lines. Each of the M lines consists of 4 integers U Lx Rx C meaning there are edges from node U to all other nodes in range [Lx , Rx] with cost C.

Example:

For N = 6 , the edge-group U = 1 , Lx = 3 , Rx = 5 , C = 10lLooks like:

Constraints:

• $$$1 \le N \le 10^5$$$
• $$$1 \le M \le 10^5$$$
• $$$1 \le U \le N$$$
• $$$1 \le Lx \le Rx \le N$$$
• $$$1 \le C \le 10^9$$$

Initial Thought Process:

• The main problem faced here is that in the worst case, we have plenty of edges $$$O(N^2)$$$, performing Dijkstra in this dense graph would lead to time complexity $$$O(N^2 log(N))$$$ which would lead to TLE. Also, it is not possible to store all edges in adjacency list, which would lead to MLE.
• So we have to seek out some ways to reduce the number of edges so that time complexity can be improved.
• Our solution proceeds like this, we first try to convert this dense graph to a sparse graph with less number of edges and then perform Dijkstra Algorithm to find our answer.
• Since the input of edges is given in compressed format, there might be some ways to represent a group of edges as a single edge so that we can reduce the number of edges and solve our problem.

Solution: Segment Tree as a structure:

• One main observation in this problem is that we add edges from node U to a range of nodes [Lx, Rx]. This gives an intuition that we deal with ranges and we can use segment trees to solve our problem.
• First, we build a segment tree $$$G'$$$ with $$$N$$$ leaf nodes, ($$$2N$$$ nodes in total). These N leaf nodes represent the N nodes of the original graph $$$G$$$.
  Example N = 8
• It is a well known fact that any range [Lx , Rx] can be covered by $$$O(log(N))$$$ nodes in a segment tree. So for every edge-group U Lx Rx C, we add edges from node U to these $$$O(log(N))$$$ nodes with cost C.

Example: N = 8, U = 1, [Lx,Rx] = [3,8], C = 10