Math,Gcd

Правка en5, от sahasumit288, 2016-10-15 22:33:31

n is a number and n=(p1^c) * (p2^d).Here p1 and p2 are prime. Let a=p1^c and b=p2^d.

gcd(i,n)= gcd(i,a) * gcd(i,b)

How to prove this? Any explanation? Thanks in advance.

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  Rev. Язык Кто Когда Δ Комментарий
en5 Английский sahasumit288 2016-10-15 22:33:31 3 Tiny change: 'b)\n\nHow can to prove ' -> 'b)\n\nHow to prove '
en4 Английский sahasumit288 2016-10-15 22:29:28 2 Tiny change: 'gcd(i,b)\nHow can ' -> 'gcd(i,b)\n\nHow can '
en3 Английский sahasumit288 2016-10-15 22:28:23 79
en2 Английский sahasumit288 2016-10-15 22:26:07 3
en1 Английский sahasumit288 2016-10-15 22:25:19 216 Initial revision (published)