Why do unsigned integers wrap without extensively using the modulo operator in c++?? Suppose , Unsigned int a , b; a and b both are 2^32-1. Then what will be the value of a+b?
so if they don't overflow how can we make them overflow??
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Unsigned integer
Why do unsigned integers wrap without extensively using the modulo operator in c++?? Suppose , Unsigned int a , b; a and b both are 2^32-1. Then what will be the value of a+b?
so if they don't overflow how can we make them overflow??
Rev. | Язык | Кто | Когда | Δ | Комментарий | |
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en2 | avik26091998 | 2017-10-08 13:54:31 | 13 | Tiny change: ' both are greater than 2^32-1.\n' -> ' both are 2^32-1.\n' | ||
en1 | avik26091998 | 2017-10-08 11:47:07 | 270 | Initial revision (published) |
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