hello codeforces
this problem 917A - Монстр has only a greedy solution which is well explained in the editorial
however i want to introduce a Dynamic programming solution
O(N^4) DP solution : 34679276
Explanation :
`the boolean solve function finds out if a certain substring can be a valid sequence of brackets
if it finds a question mark it treats it like an open bracket then a closed bracket ---complexity O(n^2)
the main function calls the solve function for every different substring which is nearly N^2 substring
so the overall complexity is O(N^4)`
O(N^3) DP solution : 34680960
Explanation :
`like the previous solution the main function calls solve function n^2 times but this time
solve function is O(n^2) n times and the rest of the calls is O(1) `
Nearly O(N^2) Accepted DP solution : 35227974 i know that this solutions seems very weird compared to the previous solutions but actually it's doing the same thing efficiently Explanation:
`now we know that in the previous solutions solve(pos,nopen) goes to states solve(pos+1,nopen+1),solve(pos+1,nopen-1)
if string[pos] was a question mark and solve(pos,nopen) goes to solve(pos+1,nopen+1) if it was an open bracket
and solve(pos+1,nopen-1) if it was a closed bracket
now let's put all these states in an array
example :
if the input string was "((?)"
the array should contain:
[0] meaning solve(0,0) then [1] meaning solve(1,1) [2] meaning solve(2,2) [1,3] meaning solve(3,1) and solve(3,3) [0,2] meaning solve(4,0) and solve(4,2) notice that we don't need to save the first parameter in the array as all states has the same level now we observe that if there's an open bracket we have to increase all array elements by 1 and -1 in case of closing brackets and in case of question mark all states is increased by 1 and new state is added which is equal to first state -2
do it yourself
now after every iteration we only have to increment our answer if there's an element in the array equal to zero`
hope you got it
important notes :
-please feel free to comment if you find any mistake in my blog
-i'm not really good at writing blogs so i'm sorry if you find bad styling or poor english
- i hope that this workaround help anyone optimizing similar DP solutions
-it took me around a month to come up with this solution and i really want to know if i'm doing problem solving efficiently
thanks