Optimal Matching

Правка en3, от saccha_hindu_bhakt, 2020-05-21 15:17:08

We have a matrix of n*n. Entries are only 0 or 1. Now we need to come up with some matching (vertical or horizontal) for 1's such that 2 1's can be matched. No 0's can be converted to 1 or vice versa. Also, a 1 can be matched to only a single 1, in simple words we cannot a single 1 to two or more 1.

We need to print Yes if there's a matching exist such that all 1's are paired or No if not. If Yes, then print all the matching as well. Print any solution if there are multiple matching for a case.

Example-

Input 4

0011

1110

1110

1111

Output Yes

(1,3)(1,4)

(2,1)(3,1)

(2,2)(3,2)

(2,3)(3,3)

(4,1)(4,2)

(4,3)(4,4)

For n<=200. This can be done by Maximum Bipartite Matching. But can't really do it.

История

 
 
 
 
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  Rev. Язык Кто Когда Δ Комментарий
en5 Английский saccha_hindu_bhakt 2020-05-21 20:27:39 22 Tiny change: 'My bad' -> 'ABC'
en4 Английский saccha_hindu_bhakt 2020-05-21 20:25:55 774
en3 Английский saccha_hindu_bhakt 2020-05-21 15:17:08 20
en2 Английский saccha_hindu_bhakt 2020-05-21 15:16:27 6
en1 Английский saccha_hindu_bhakt 2020-05-21 15:15:21 746 Initial revision (published)