We will hold AtCoder Beginner Contest 444.
- Contest URL: https://atcoder.jp/contests/abc444
- Start Time: http://www.timeanddate.com/worldclock/fixedtime.html?iso=20260207T2100&p1=248
- Duration: 100 minutes
- Writer: vwxyz0, kyopro_friends, ynymxiaolongbao, toam
- Tester: Nyaan, cn449
- Rated range: ~ 1999
- The point values: 100-200-350-400-450-550-675
675 pointer G!! Seems like it's going to be speed run for problems A-F :(
My bad :(
It was just A-E.
speed really matters on atcoder
Speed matters on every platform but when there is such a gap b/w problems E and F for even the IGMs, that's not a good sign. And this was not even an ARC but AGC. Having two problems of this calibre in an ABC is demotivating!
Not a good round I think. Penalties really matters on atcoder. The first person solving from A to E got rank 53, but the last only got rank 2454.
Hardest F ever
Hope everyone good luck!
Hardest G ever...
good
Hope everybody luck in all the contest!
Good luck!
Why do I get a 403 ERROR? The server is busy?
Why there's a 403 ERROR?I haven't submitted the problem A for the first 30 minutes
Good Luck!
hey i have been automatically registered as unrated how can i switch to rated
I guess that you can't switch to rated. I tried that several months ago and failed. And if you switch,your rating will become lower.
do you have any idea why i was automatically registered as unrated
maybe it's because you participate too late.
as the website said:
(in https://atcoder.jp/posts/745)
omg
I preemptively award F "most annoying problem of the year" for 2026.
I support u
Indeed.
i support u.
indeed
I support u
I couldn’t join the contest because I had a physics class... :<
The gap between E and F is TOOOOOOOOOOO large. 2411 participants passed A~E (scoring 1500), but only 54 participants passed F (including AI?). The sample input for F is also very weak. I coded a solution for F with all my might but it ended up getting a verdict of AC×40 and TLE×10.
Can someone please help with C. This is my submission. https://atcoder.jp/contests/abc444/submissions/73102557 I basically tried two cases after sorting — one where the last element==l and then I make sure other pairs exist.
And case two with even pair after sorting such that I sum i th element from both start and end and see if their sums are equal.
Consider this case, the output should be empty, but your code prints $$$10$$$. I know the problem guarantees that at least one solution exists, but any correct implementation would produce no output for this case, which indicates that your code may print an invalid answer in real tests.
Thanks a lot. I debugged with it and found the issue.
F and G is soooooooo hard. It took me 75 min to solve G and i don't have time to solve F.
Probably hardest F ever, I don't have any idea when i read the problem statement. It would be better if F is easier.
not so good round, i think.
Prob D is a little bit easier than Prob C, and the gap between E and F is too big that solving A-E may have perf from 1200 to 2300
I agree. I think C is easier
What a F
https://atcoder.jp/contests/abc444/editorial/15843
For the end of the problem G editorial, what does the periodicity of $$$\pi_p^k\pmod C$$$ say about the periodicity of $$$p^{k_p}\pi_p^{e_p-2k_p}\pmod C$$$?
Upd: If you split $$$C$$$ into the portion divisible by $$$p$$$ and the other portion, then $$$p^{k_p}\pi_p^{e_p-2k_p}$$$ will be zero modulo the first portion for all but some small values of $$$k_p$$$, and purely periodic modulo the second portion.
SpeedCoder. Gap between E and F is too much
Problem F : In the following submission why am I getting WA. Don't worry about TLE.
My submission
ZJG Contest
Is there a way to apply the idea behind Problem G to non-math problems?
I learned a lot about Gaussian integers and filled some gaps in my number theory knowledge. However, I am curious how this knowledge can be apply to CP problems.
Of course, this might not actually exist, but knowledge is always useful, and it better to learn it than not.
Can we talk AWC there?