Any idea about how to solve http://acm.tju.edu.cn/toj/showp2463.html ?
I guess dp approach doesn't work here.
I guess dp approach doesn't work here.
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Название |
---|
Let's build suffix tree for string s = s1a1s2a2...skak, where a is set of different delimeters (si don't contains aj ). Consider leaf of builded tree. Let's define color[v] (where v is leaf) as first delimeter symbol which contains suffix of this leaf. Then if vertex has x colors in its subtree then string on this vertex is common string of x given strings. So if it contains k colors it's common string for all given strings. So we need found number of colors in subtree of each vertex. It can be solved using DFS, DSU and Tarjan algorithm. And finally we need only find the deepest vertex which contains k colors. Final complexity is O(n * α(n)), where α(n) is inverse of Ackerman function, and n is sum of strings' lengthes