i hope problems be cool like announcement :)

Technically, no, since this is a Div.2-only contest.

i.e. C.Master participants are also rated.

It will be rated for everybody up to 2100. Participants with the ratings 2100+ are invited to take part unofficially.

Both googling 'codeforces round cyand1317' and viewing their blog suffice; the other rounds are #418 and #431.

Your words seem more of that of a poet rather than of a coder.

It is not

I can confirm.

Let's hope it will! (Looks worriedly at the list of red-orange registrants and then problem E...)

Still everyone talks about the same. :( YES IT IS RATED FOR YOU

There are a few [not] easy ways:

1. Writing really useful comments.
2. Writing really funny comments.
3. Using breaking news to make a funny comment.

Updated, thank you!

No, but they'll say interesting Hitokoto-word-kotoba's like Mio and Yuko do.

I think it happens concurrently with this round as default, where you can start hacking others on a specific problem after passing pretests and locking it.

Yes. EDIT:

Only the normal room hacking.

He did mention in the blog that you can skip the additional story..

Maybe I got the mistake in my thinking :|

I was trying to find the answer for individual lines only, disregarding the fact that multiple lines can coincide :|

But then this probably makes the problem much harder than what I thought during contest

Make a quarter for each letter, that will consume 1 component of each, and each group will have 25*25 letters. e.g:

AAAAABBBBB
AAAAABBBBB
AAAAABBBBB
CCCCCDDDDD
CCCCCDDDDD
CCCCCDDDDD

Now put the rest of each letter inside the quarter of any other letter without touching each other, that way, each letter will have up to 12*12 components to create. e.g:

AAAAABBBBB
ABABABCBCB
AAAAABBBBB
CCCCCDDDDD
CDCDCDADAD
CCCCCDDDDD

Let the answer always be a grid of size 50 * 50
Initially fill the left half with A's and the right half with B's
Now to fill the remaining components make "holes" in each of the halves and place them accordingly.
Suppose a = 3, b = 3, c = 2, d = 2
The matrix will be (note that the actual matrix will have size 50 * 50 )
AAAAA | BBBBB
ABABA | BABAB
AAAAA | BBBBB
ACACA | BDBDB

make 50 50 matrix , use 1 component of B to make all components of A , 1 of C to make rest of B and similarly for the rest. like if input is 4 4 4 4 ,then matrix would look like

BBBBBBBBBBB(...upto 50 chars)

ABABABBBBBB

BBBBBBBBBBB

CCCCCCCCCCC

BCBCBCCCCCC

CCCCCCCCCCC

DDDDDDDDDDD

CDCDCDDDDDD

DDDDDDDDDDD

AAAAAAAAAAA

DADADAAAAAA

AAAAAAAAAAA

If p=n, then p is always a period. In other words, if x is the length of the string s, then x is a period of string s.

Representing the time with a vertical axis will help save quite a little ink and paper. Just two different approaches :)

I thought C is pretty simple? Just fill the first 25 rows with A, the last 25 rows with B, and change the cells with even row and even column until there's enough connected component of each type.

Incorrectly estimated difficulties T^T

The real problem is less than 100 people solved D&E.

Not sure about simplest but this is how I did it. Use the whole 50x50 array. Fill in top half with A, bottom half with B. It sort of looks like a grid jail. Put C's and D's in alternating spots. Put remaining A's in bottom half and B's in top half.

You can paint the four squares of 25x25 like this:

AB

CD

and then in the square with the A you paint the D's you need in the tiles with both x and y even, do this for the other three squares and you are done. It works because 25x24/4>100

May be it will help u. I hacked some people by this test: 5 3

1..1.

You can also observe that both problems were set by the same person... :)

Actually they are similar in statement only: solving one problem can't help you solve the other one.

When I saw problem 989D - A Shade of Moonlight initially, I misread it and couldn't solve, but solved another problem instead. That is how 956D - Contact ATC was created.

only if it fails on pretest 1

only if it fails on 1st pretest,then you won't get any penalty.