How to efficiently calculate the value of $$$ \frac{3^{n}-1}{2} $$$ modulo an even number $$$ p $$$, when the bound on $$$ n $$$ is up to $$$ 10^{18} $$$ and $$$ p $$$ is up to $$$ 10^9 $$$?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3773 |
3 | Radewoosh | 3646 |
4 | ecnerwala | 3624 |
5 | jqdai0815 | 3620 |
5 | Benq | 3620 |
7 | orzdevinwang | 3612 |
8 | Geothermal | 3569 |
8 | cnnfls_csy | 3569 |
10 | gyh20 | 3447 |
# | User | Contrib. |
---|---|---|
1 | awoo | 161 |
2 | maomao90 | 160 |
3 | nor | 157 |
4 | atcoder_official | 156 |
4 | cry | 156 |
6 | -is-this-fft- | 155 |
7 | maroonrk | 154 |
8 | adamant | 153 |
9 | Um_nik | 151 |
10 | djm03178 | 146 |
How to efficiently calculate the value of $$$ \frac{3^{n}-1}{2} $$$ modulo an even number $$$ p $$$, when the bound on $$$ n $$$ is up to $$$ 10^{18} $$$ and $$$ p $$$ is up to $$$ 10^9 $$$?
Name |
---|
If
is odd,
is odd, else it is even.
If $$$ka = kb \text{ (mod } km)$$$, then $$$a = b \text{ (mod } m)$$$.
Thus, you can compute $$$x \text{ (mod } 2p)$$$ and then divide by 2 to get $$$x/2 \text{ (mod } p)$$$ (in this example, $$$x = 3^n-1$$$).
Thanks