Given an interval [L, R]. Given an array of intervals in the form of Li and Ri. How many minimum intervals required to cover the range [L, R]? Intervals can overlap with each other. L>=1 && R<=1e5 Li>=1 && Ri<=1e5 The size of the array <= 1e5
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Given an interval [L, R]. Given an array of intervals in the form of Li and Ri. How many minimum intervals required to cover the range [L, R]? Intervals can overlap with each other. L>=1 && R<=1e5 Li>=1 && Ri<=1e5 The size of the array <= 1e5
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Auto comment: topic has been updated by Finding_Infinity (previous revision, new revision, compare).
I think it can be done by sorting and pointers:
Sort the intervals according to 'r' and if two intervals have same 'r' choose the interval having max diff of |r-l|. After that remove(ignore) all intervals having same 'r' except the one which have maximum difference of |r-l|.
Now starting from any interval having r>=R which intersects R, move towards left up_to and also make a variable eg: maxL , which stores the maximum l you ever reached. If maxL becomes smaller than the current interval's l then update maxL and increase the count.
Stop when you reach the desired L, and print the count.
I think this should work.
initially , count = 1.
Start increasing count when you've come the left of R.